The problem presents a simply supported beam with two point loads. The beam is supported at points A and C. A downward force of $60 \text{ kN}$ is applied at point B, which is $2 \text{ m}$ from A. A downward force of $30 \text{ kN}$ is applied at point D, which is $1 \text{ m}$ beyond point C. The reactions at A and C are $R_1 = 35 \text{ kN}$ and $R_2 = 55 \text{ kN}$, respectively. The shear force and bending moment diagrams are also provided. The question does not explicitly state what needs to be calculated. I will summarize key information from the diagrams.

1. Problem Description

The problem presents a simply supported beam with two point loads. The beam is supported at points A and C. A downward force of $60 \text{ kN}$ is applied at point B, which is $2 \text{ m}$ from A. A downward force of $30 \text{ kN}$ is applied at point D, which is $1 \text{ m}$ beyond point C. The reactions at A and C are $R_1 = 35 \text{ kN}$ and $R_2 = 55 \text{ kN}$, respectively. The shear force and bending moment diagrams are also provided. The question does not explicitly state what needs to be calculated. I will summarize key information from the diagrams.

2. Solution Steps

From the shear diagram:

The shear force between A and B is $35 \text{ kN}$.

The shear force between B and C is $-25 \text{ kN}$.

The shear force between C and D is $30 \text{ kN}$.

From the moment diagram:

The maximum positive moment occurs at B and is $70 \text{ kN-m}$.

The moment at D is $-30 \text{ kN-m}$.

The bending moment at A and C are both

0.

3. Final Answer

Maximum positive bending moment: $70 \text{ kN-m}$

Bending moment at D: $-30 \text{ kN-m}$