The problem asks to factor the expression $ab - 3a + 15 - 5b$.

AlgebraFactorizationAlgebraic ManipulationGrouping
2025/3/22

1. Problem Description

The problem asks to factor the expression ab3a+155bab - 3a + 15 - 5b.

2. Solution Steps

First, we rearrange the terms:
ab3a5b+15ab - 3a - 5b + 15
Now, we factor by grouping. From the first two terms, we can factor out an aa:
a(b3)5b+15a(b - 3) - 5b + 15
From the last two terms, we can factor out a 5-5:
a(b3)5(b3)a(b - 3) - 5(b - 3)
Now we have a common factor of (b3)(b - 3):
(b3)(a5)(b - 3)(a - 5)
So the factored expression is (a5)(b3)(a-5)(b-3).

3. Final Answer

(a5)(b3)(a-5)(b-3)

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