The problem asks us to find the values of $a$ and $b$ in the expression $ax^3 - x^2 + bx - 1$, given that when divided by $x+2$ the remainder is $-33$, and when divided by $x-3$ the remainder is $77$. We are then asked to find the remainder when the expression is divided by $x-2$.

AlgebraPolynomialsRemainder TheoremSystem of EquationsCubic Polynomials
2025/5/18

1. Problem Description

The problem asks us to find the values of aa and bb in the expression ax3x2+bx1ax^3 - x^2 + bx - 1, given that when divided by x+2x+2 the remainder is 33-33, and when divided by x3x-3 the remainder is 7777. We are then asked to find the remainder when the expression is divided by x2x-2.

2. Solution Steps

We use the Remainder Theorem, which states that if we divide a polynomial f(x)f(x) by xcx-c, the remainder is f(c)f(c).
* Step 1: Apply the Remainder Theorem for x+2x+2
Since dividing by x+2x+2 gives a remainder of 33-33, we have f(2)=33f(-2) = -33. Substituting x=2x = -2 into the expression gives:
a(2)3(2)2+b(2)1=33a(-2)^3 - (-2)^2 + b(-2) - 1 = -33
8a42b1=33-8a - 4 - 2b - 1 = -33
8a2b5=33-8a - 2b - 5 = -33
8a2b=28-8a - 2b = -28
4a+b=144a + b = 14 (Equation 1)
* Step 2: Apply the Remainder Theorem for x3x-3
Since dividing by x3x-3 gives a remainder of 7777, we have f(3)=77f(3) = 77. Substituting x=3x = 3 into the expression gives:
a(3)3(3)2+b(3)1=77a(3)^3 - (3)^2 + b(3) - 1 = 77
27a9+3b1=7727a - 9 + 3b - 1 = 77
27a+3b10=7727a + 3b - 10 = 77
27a+3b=8727a + 3b = 87
9a+b=299a + b = 29 (Equation 2)
* Step 3: Solve the system of equations
We have the following system of linear equations:
4a+b=144a + b = 14
9a+b=299a + b = 29
Subtracting Equation 1 from Equation 2, we get:
(9a+b)(4a+b)=2914(9a + b) - (4a + b) = 29 - 14
5a=155a = 15
a=3a = 3
Substituting a=3a=3 into Equation 1:
4(3)+b=144(3) + b = 14
12+b=1412 + b = 14
b=2b = 2
* Step 4: Find the remainder when divided by x2x-2
Now that we know a=3a=3 and b=2b=2, the expression is 3x3x2+2x13x^3 - x^2 + 2x - 1.
We want to find the remainder when divided by x2x-2.
Using the Remainder Theorem, we need to find f(2)f(2):
f(2)=3(2)3(2)2+2(2)1f(2) = 3(2)^3 - (2)^2 + 2(2) - 1
f(2)=3(8)4+41f(2) = 3(8) - 4 + 4 - 1
f(2)=244+41f(2) = 24 - 4 + 4 - 1
f(2)=23f(2) = 23

3. Final Answer

a=3a = 3, b=2b = 2, and the remainder when divided by x2x-2 is
2
3.

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