A bridge of length $5\frac{1}{2}$ km was to be constructed. Company A constructed $2\frac{4}{5}$ km of the bridge. Then, a part of the constructed bridge got damaged. Company B then constructed a total of $4\frac{1}{3}$ km, which included the damaged part and the remaining part of the bridge. We need to find the length of the part that was damaged.

ArithmeticFractionsMixed NumbersWord ProblemAdditionSubtraction
2025/3/7

1. Problem Description

A bridge of length 5125\frac{1}{2} km was to be constructed. Company A constructed 2452\frac{4}{5} km of the bridge. Then, a part of the constructed bridge got damaged. Company B then constructed a total of 4134\frac{1}{3} km, which included the damaged part and the remaining part of the bridge. We need to find the length of the part that was damaged.

2. Solution Steps

First, we find the length of the bridge remaining after Company A's construction:
5122455\frac{1}{2} - 2\frac{4}{5}
Convert mixed numbers to improper fractions:
512=5×2+12=1125\frac{1}{2} = \frac{5 \times 2 + 1}{2} = \frac{11}{2}
245=2×5+45=1452\frac{4}{5} = \frac{2 \times 5 + 4}{5} = \frac{14}{5}
112145=11×52×514×25×2=55102810=552810=2710\frac{11}{2} - \frac{14}{5} = \frac{11 \times 5}{2 \times 5} - \frac{14 \times 2}{5 \times 2} = \frac{55}{10} - \frac{28}{10} = \frac{55 - 28}{10} = \frac{27}{10}
So, the remaining length of the bridge after Company A's construction is 2710\frac{27}{10} km.
Let dd be the length of the damaged part. Company B constructed 4134\frac{1}{3} km, which included the damaged part dd and the remaining part of the bridge, which is 2710d\frac{27}{10} - d. Thus,
413=d+(2710d)4\frac{1}{3} = d + (\frac{27}{10} - d) is incorrect. Company B constructed the damaged part plus the remaining part, so the total length of bridge constructed by A which is 2452\frac{4}{5} km is equal to the length constructed by B which is 4134\frac{1}{3} km plus the damaged part dd. Therefore we have:
245=413+d2\frac{4}{5} = 4\frac{1}{3} + d is incorrect.
The length constructed by A 2452\frac{4}{5} km included the damaged part (dd) and undamaged part. The length of the bridge remaining after A constructed is 2710\frac{27}{10} km. Company B constructed 4134\frac{1}{3} km, which equals the remaining part of the bridge. The equation should be:
A’s constructionDamaged part+Company B’s construction=Total length\text{A's construction} - \text{Damaged part} + \text{Company B's construction} = \text{Total length}
245d+2710A (wrong expression)2\frac{4}{5} - d + \frac{27}{10} - A \text{ (wrong expression)}
Then,
245d=Length constructed by A that is not damaged2\frac{4}{5} - d = \text{Length constructed by A that is not damaged}
Since company B constructed damaged part dd + remaining part after A. Then the equation should be: 4134\frac{1}{3} = (remaining after A, i.e. total length - length constructed by A ) + d.
Therefore: 413=512245+d=2710+d4\frac{1}{3} = 5\frac{1}{2} - 2\frac{4}{5} + d = \frac{27}{10} + d
Convert 4134\frac{1}{3} to an improper fraction: 413=4×3+13=1334\frac{1}{3} = \frac{4 \times 3 + 1}{3} = \frac{13}{3}
Then, we have 133=2710+d\frac{13}{3} = \frac{27}{10} + d. Therefore,
d=1332710=13×103×1027×310×3=130308130=1308130=4930d = \frac{13}{3} - \frac{27}{10} = \frac{13 \times 10}{3 \times 10} - \frac{27 \times 3}{10 \times 3} = \frac{130}{30} - \frac{81}{30} = \frac{130 - 81}{30} = \frac{49}{30}
Now we convert the improper fraction to mixed number:
4930=11930\frac{49}{30} = 1\frac{19}{30}

3. Final Answer

119301\frac{19}{30}

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