The image shows a triangle with one angle labeled as $42^{\circ}$. The problem asks to find the angle 'c'. It is assumed that 'c' refers to the angle at the bottom right of the triangle. The triangle appears to be isosceles, meaning two of its sides are equal. If the triangle is isosceles, then the two angles opposite the equal sides are also equal.

GeometryTrianglesAnglesIsosceles TriangleAngle Sum Property
2025/5/19

1. Problem Description

The image shows a triangle with one angle labeled as 4242^{\circ}. The problem asks to find the angle 'c'. It is assumed that 'c' refers to the angle at the bottom right of the triangle. The triangle appears to be isosceles, meaning two of its sides are equal. If the triangle is isosceles, then the two angles opposite the equal sides are also equal.

2. Solution Steps

Step 1: Assume the triangle is isosceles.
If the triangle is isosceles, then the angle opposite the side adjacent to the 4242^{\circ} angle is also 4242^{\circ}. Let the three angles of the triangle be AA, BB, and CC. We are given that A=42A = 42^{\circ}. If the triangle is isosceles, then B=42B = 42^{\circ}.
Step 2: Calculate the third angle.
The sum of the angles in a triangle is 180180^{\circ}.
A+B+C=180A + B + C = 180^{\circ}
42+42+C=18042^{\circ} + 42^{\circ} + C = 180^{\circ}
84+C=18084^{\circ} + C = 180^{\circ}
C=18084C = 180^{\circ} - 84^{\circ}
C=96C = 96^{\circ}
Step 3: Determine if the assumption holds.
If the triangle is isosceles and the angle at the top is 4242^{\circ}, then the base angles are equal, and their sum is 18042=138180^{\circ} - 42^{\circ} = 138^{\circ}. Each base angle would be 138/2=69138^{\circ}/2 = 69^{\circ}. However, the number next to the triangle on the image is 97, so angle C is equal to 9797^{\circ}. Let's calculate what that makes the third angle.
Step 4: Recalculate the unknown angle.
42+C=180B42^{\circ} + C = 180^{\circ} - B
Since the value 97 seems to be closer to CC, let us assume C=97C=97^{\circ}. Then 42+B+97=18042^{\circ} + B + 97^{\circ} = 180^{\circ}
B=180(42+97)=180139=41B = 180^{\circ} - (42^{\circ} + 97^{\circ}) = 180^{\circ} - 139^{\circ} = 41^{\circ}
Thus angle C is 9797^{\circ}

3. Final Answer

96

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