We are given a triangle with one angle measuring $42^{\circ}$. We are asked to find the measure of the angle labeled $c$. The angle $c$ appears to be an exterior angle to the triangle. We are also given a number 97. I assume it is asking for $c$ degrees.

GeometryTrianglesAnglesExterior AnglesAngle Sum Property
2025/5/19

1. Problem Description

We are given a triangle with one angle measuring 4242^{\circ}. We are asked to find the measure of the angle labeled cc. The angle cc appears to be an exterior angle to the triangle. We are also given a number
9

7. I assume it is asking for $c$ degrees.

2. Solution Steps

The exterior angle of a triangle is equal to the sum of the two non-adjacent interior angles.
Since the angle cc is an exterior angle, we need to find the two non-adjacent interior angles. One of the angles is 4242^{\circ}. The other interior angle is not given in the picture.
Based on the figure, it seems that angle cc is supplementary to one of the angles in the triangle. Let that angle be xx. Then, x+c=180x + c = 180. Also, the sum of the three angles in a triangle is
1
8

0. Let the other interior angle be $a$. Then $42 + x + a = 180$.

Also, c=42+ac = 42 + a
a=c42a = c - 42
Substituting a=c42a = c - 42 into 42+x+a=18042 + x + a = 180, we have
42+x+c42=18042 + x + c - 42 = 180
x+c=180x + c = 180.
Therefore, xx and cc are supplementary angles.
It looks like the exterior angle is 9797^{\circ}. Thus c=97c = 97.
Then x=180c=18097=83x = 180 - c = 180 - 97 = 83.
Also, a=c42=9742=55a = c - 42 = 97 - 42 = 55.
The sum of the angles in the triangle is 42+83+55=18042 + 83 + 55 = 180.

3. Final Answer

The value of cc is
9
7.

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