The problem asks us to find the surface area of a cylinder (a can) with a radius of 3 inches and a height of 2.3 inches. We need to round our answer to the nearest tenth of a square inch.

1. Problem Description

The problem asks us to find the surface area of a cylinder (a can) with a radius of 3 inches and a height of 2.3 inches. We need to round our answer to the nearest tenth of a square inch.

2. Solution Steps

The formula for the surface area of a cylinder is:

$SA = 2 \pi r^2 + 2 \pi r h$

where $r$ is the radius and $h$ is the height.

In this case, $r = 3$ and $h = 2.3$. Plugging these values into the formula:

$SA = 2 \pi (3)^2 + 2 \pi (3)(2.3)$

$SA = 2 \pi (9) + 2 \pi (6.9)$

$SA = 18 \pi + 13.8 \pi$

$SA = 31.8 \pi$

Using the $\pi$ button on a calculator, we get:

$SA \approx 31.8 \times 3.14159265359 \approx 100.02656$

Rounding to the nearest tenth of a square inch, we get $100.0$.

3. Final Answer

100.0 in$^2$