The problem asks us to solve for $x$ in each of the given equations.

1. Problem Description

The problem asks us to solve for $x$ in each of the given equations.

2. Solution Steps

i) $307 + 49 = 49 + x$

Subtract 49 from both sides:

$307 + 49 - 49 = 49 + x - 49$

$307 = x$

ii) $476 + 24 = x + 476$

Subtract 476 from both sides:

$476 + 24 - 476 = x + 476 - 476$

$24 = x$

iii) $93 + 167 = 167 + x$

Subtract 167 from both sides:

$93 + 167 - 167 = 167 + x - 167$

$93 = x$

iv) $3500 + 2000 = x + 3500$

Subtract 3500 from both sides:

$3500 + 2000 - 3500 = x + 3500 - 3500$

$2000 = x$

i) $(7 + 4) + 5 = 7 + (x + 5)$

$11 + 5 = 7 + x + 5$

$16 = 12 + x$

Subtract 12 from both sides:

$16 - 12 = 12 + x - 12$

$4 = x$

ii) $18 + (10 + 43) = (x + 10) + 43$

$18 + 53 = x + 10 + 43$

$71 = x + 53$

Subtract 53 from both sides:

$71 - 53 = x + 53 - 53$

$18 = x$

iii) $(11 + x) + 13 = 11 + (8 + 13)$

$11 + x + 13 = 11 + 21$

$24 + x = 32$

Subtract 24 from both sides:

$24 + x - 24 = 32 - 24$

$x = 8$

iv) $x + (19 + 7) = (41 + 19) + 7$

$x + 26 = 60 + 7$

$x + 26 = 67$

Subtract 26 from both sides:

$x + 26 - 26 = 67 - 26$

$x = 41$

3. Final Answer

i) $x = 307$

ii) $x = 24$

iii) $x = 93$

iv) $x = 2000$

i) $x = 4$

ii) $x = 18$

iii) $x = 8$

iv) $x = 41$