The problem is to evaluate $27^{-1/3}$.

ArithmeticExponentsRadicalsSimplification
2025/3/8

1. Problem Description

The problem is to evaluate 271/327^{-1/3}.

2. Solution Steps

We are asked to evaluate 271/327^{-1/3}.
First, we can rewrite 27 as 333^3. So, the expression becomes (33)1/3(3^3)^{-1/3}.
Using the power of a power rule, we have 33(1/3)=313^{3 \cdot (-1/3)} = 3^{-1}.
A number raised to a negative exponent is the reciprocal of that number raised to the positive exponent, so 31=131=133^{-1} = \frac{1}{3^1} = \frac{1}{3}.
xn=1xnx^{-n} = \frac{1}{x^n}

3. Final Answer

13\frac{1}{3}

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