The problem is to evaluate the expression $(-2)^4 \times (-\frac{1}{2})^3$.

1. Problem Description

The problem is to evaluate the expression $(-2)^4 \times (-\frac{1}{2})^3$.

2. Solution Steps

First, evaluate $(-2)^4$.

Since the exponent is an even number, the result will be positive.

$(-2)^4 = (-2) \times (-2) \times (-2) \times (-2) = 16$

Next, evaluate $(-\frac{1}{2})^3$.

Since the exponent is an odd number, the result will be negative.

$(-\frac{1}{2})^3 = (-\frac{1}{2}) \times (-\frac{1}{2}) \times (-\frac{1}{2}) = -\frac{1}{8}$

Now, multiply the two results.

$16 \times (-\frac{1}{8}) = -\frac{16}{8} = -2$

3. Final Answer

The final answer is -2.