The problem asks us to convert the equation $4x + \frac{3}{4}y = -3$ into slope-intercept form ($y = mx + b$), and then identify the slope ($m$) and the y-intercept (the point $(0, b)$). The provided solution states that the equation in slope intercept form is $y = -\frac{16}{3}x - 4$. We must then state the slope and y-intercept based on this equation.

1. Problem Description

The problem asks us to convert the equation $4x + \frac{3}{4}y = -3$ into slope-intercept form ($y = mx + b$), and then identify the slope ($m$) and the y-intercept (the point $(0, b)$). The provided solution states that the equation in slope intercept form is $y = -\frac{16}{3}x - 4$. We must then state the slope and y-intercept based on this equation.

2. Solution Steps

First, we isolate $y$ in the given equation $4x + \frac{3}{4}y = -3$.

Subtract $4x$ from both sides:

$\frac{3}{4}y = -4x - 3$

Multiply both sides by $\frac{4}{3}$:

$y = \frac{4}{3}(-4x - 3)$

$y = \frac{4}{3}(-4x) + \frac{4}{3}(-3)$

$y = -\frac{16}{3}x - 4$

So, the equation in slope-intercept form is $y = -\frac{16}{3}x - 4$. The slope $m$ is $-\frac{16}{3}$. The y-intercept is the point where $x = 0$, so $y = -\frac{16}{3}(0) - 4 = -4$. The y-intercept as an ordered pair is $(0, -4)$.

3. Final Answer

Slope = $-\frac{16}{3}$

y-intercept = $(0, -4)$