We are given the set $S = \{1, 2, 3, 4, 5, 6\}$. We need to find the cardinality (number of elements) of the Cartesian product $S \times S$. The Cartesian product $S \times S$ is the set of all ordered pairs $(a, b)$ where $a \in S$ and $b \in S$. We can find $|S \times S|$ by listing all its elements, or more easily, by calculating $|S| \times |S|$.

Discrete MathematicsSet TheoryCartesian ProductCardinality
2025/5/27

1. Problem Description

We are given the set S={1,2,3,4,5,6}S = \{1, 2, 3, 4, 5, 6\}. We need to find the cardinality (number of elements) of the Cartesian product S×SS \times S. The Cartesian product S×SS \times S is the set of all ordered pairs (a,b)(a, b) where aSa \in S and bSb \in S. We can find S×S|S \times S| by listing all its elements, or more easily, by calculating S×S|S| \times |S|.

2. Solution Steps

First, we find the cardinality of the set SS. Since S={1,2,3,4,5,6}S = \{1, 2, 3, 4, 5, 6\}, the number of elements in SS is

6. So, $|S| = 6$.

The Cartesian product S×SS \times S consists of ordered pairs (a,b)(a, b) where aSa \in S and bSb \in S. The number of elements in the Cartesian product S×SS \times S is given by
S×S=S×S|S \times S| = |S| \times |S|.
Substituting S=6|S| = 6, we have
S×S=6×6=36|S \times S| = 6 \times 6 = 36.
Listing the elements of S×SS \times S is possible but tedious. Here is the beginning:
S×S={(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(6,6)}S \times S = \{(1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (2,1), (2,2), (2,3), (2,4), (2,5), (2,6), (3,1), \dots (6,6) \}. There are 6 rows and 6 columns, thus a total of 6×6=366 \times 6 = 36 elements.

3. Final Answer

S×S=36|S \times S| = 36

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