The problem asks to factor the difference of two squares: $4x^2 - 49$.

1. Problem Description

The problem asks to factor the difference of two squares: $4x^2 - 49$.

2. Solution Steps

We can use the difference of squares formula:

$a^2 - b^2 = (a - b)(a + b)$

We can identify $a$ and $b$ in the expression $4x^2 - 49$.

$4x^2$ can be written as $(2x)^2$. Therefore, $a = 2x$.

$49$ can be written as $7^2$. Therefore, $b = 7$.

Applying the difference of squares formula, we get:

$4x^2 - 49 = (2x)^2 - 7^2 = (2x - 7)(2x + 7)$

3. Final Answer

$(2x-7)(2x+7)$