Let $A = (-2, +\infty)$ and $B = [5, +\infty)$. Find the complement of $B$ on $A$, which can be denoted as $A \setminus B$ or $A - B$.

AlgebraSet TheoryIntervalsSet OperationsComplement
2025/6/14

1. Problem Description

Let A=(2,+)A = (-2, +\infty) and B=[5,+)B = [5, +\infty). Find the complement of BB on AA, which can be denoted as ABA \setminus B or ABA - B.

2. Solution Steps

The complement of BB on AA, denoted as ABA \setminus B, is the set of all elements in AA that are not in BB. In other words, AB={xxA and xB}A \setminus B = \{x \mid x \in A \text{ and } x \notin B\}.
We have A=(2,+)={x2<x<+}A = (-2, +\infty) = \{x \mid -2 < x < +\infty\} and B=[5,+)={x5x<+}B = [5, +\infty) = \{x \mid 5 \le x < +\infty\}.
We want to find ABA \setminus B, which consists of elements in AA but not in BB.
AB=(2,+)[5,+)A \setminus B = (-2, +\infty) \setminus [5, +\infty). We can express ABA \setminus B as an intersection:
AB=ABcA \setminus B = A \cap B^c, where BcB^c is the complement of BB. The complement of B=[5,+)B = [5, +\infty) is Bc=(,5)B^c = (-\infty, 5).
So, AB=(2,+)(,5)={x2<x<+ and <x<5}A \setminus B = (-2, +\infty) \cap (-\infty, 5) = \{x \mid -2 < x < +\infty \text{ and } -\infty < x < 5\}.
This intersection is the set of xx such that 2<x<5-2 < x < 5. Thus, AB=(2,5)A \setminus B = (-2, 5).
However, none of the answer choices match (2,5)(-2, 5). Let's re-examine the original text. It states "the complement of A on U". There appears to be a typo. The problem likely intended to ask for the complement of B with respect to A, or the complement of the union of A and B.
If it asked for ABA \cup B, we would have AB=(2,+)[5,+)=(2,+)A \cup B = (-2, +\infty) \cup [5, +\infty) = (-2, +\infty). If we're considering the universal set to be the real numbers R\mathbb{R}, then the complement of this is (,2](-\infty, -2].
If instead it asked for ABA \cap B, then AB=(2,+)[5,+)=[5,+)A \cap B = (-2, +\infty) \cap [5, +\infty) = [5, +\infty). Then the complement would be (,5)(-\infty, 5).
If the question intended to define U as the union of A and B, denoted as U=ABU = A \cup B, and asked to compute the complement of BB on UU, that means we want to find UBU \setminus B.
Since A=(2,+)A = (-2, +\infty) and B=[5,+)B = [5, +\infty), U=AB=(2,+)U = A \cup B = (-2, +\infty). Then UB=(2,+)[5,+)=(2,5)U \setminus B = (-2, +\infty) \setminus [5, +\infty) = (-2, 5).
Then we might be looking for [2,5][-2, 5] rather than (2,5)(-2, 5).
If the question is asking for the complement of the intersection of A and B with respect to the universal set U=RU = \mathbb{R}, then we have AB=[5,+)A \cap B = [5, +\infty). The complement of this is (,5)(-\infty, 5).
Consider the option [A] [-2, 5]. This may refer to the interval (2,5](-2, 5]. We found that AB=(2,5)A \setminus B = (-2, 5). It seems like the closest answer would be (-2, 5), where the parenthesis means that -2 and 5 are not included. However, there may be a typo and [A] is meant to be (-2, 5].
With A=(2,)A = (-2, \infty) and B=[5,)B=[5,\infty), the complement of B with respect to A is the set of all elements in A that are not in B, or ABA-B. This gives us the interval (2,5)(-2,5). It seems closest to answer choice C (-2,5).

3. Final Answer

C (-2,5)

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