The problem asks us to factor the polynomial $2a^2 - 7a + 5$ using the grouping number method.

AlgebraPolynomial FactorizationGrouping MethodQuadratic Polynomials
2025/3/25

1. Problem Description

The problem asks us to factor the polynomial 2a27a+52a^2 - 7a + 5 using the grouping number method.

2. Solution Steps

First, we need to find two numbers that multiply to 25=102 \cdot 5 = 10 and add up to 7-7.
The numbers are 2-2 and 5-5, since (2)(5)=10(-2) \cdot (-5) = 10 and (2)+(5)=7(-2) + (-5) = -7.
Now we rewrite the middle term 7a-7a as 2a5a-2a - 5a.
So, we have 2a27a+5=2a22a5a+52a^2 - 7a + 5 = 2a^2 - 2a - 5a + 5.
Next, we group the terms in pairs: (2a22a)+(5a+5)(2a^2 - 2a) + (-5a + 5).
Now, we factor out the greatest common factor (GCF) from each pair.
From the first pair, we can factor out 2a2a: 2a(a1)2a(a - 1).
From the second pair, we can factor out 5-5: 5(a1)-5(a - 1).
So, we have 2a(a1)5(a1)2a(a - 1) - 5(a - 1).
Now, we factor out the common factor (a1)(a - 1) from both terms: (a1)(2a5)(a - 1)(2a - 5).

3. Final Answer

(a1)(2a5)(a-1)(2a-5)