The problem asks to identify which of the given conditions imply that vector $a$ is parallel to vector $b$. The conditions are: 1. $a = b$

GeometryVectorsParallel VectorsVector MagnitudeScalar Multiplication
2025/3/26

1. Problem Description

The problem asks to identify which of the given conditions imply that vector aa is parallel to vector bb. The conditions are:

1. $a = b$

2. $|a| = |b|$

3. $a$ and $b$ have opposite directions

4. $|a| = 0$ or $|b| = 0$

5. $a$ and $b$ are unit vectors

2. Solution Steps

Two vectors are parallel if one is a scalar multiple of the other. This means a=kba = kb for some scalar kk.
Condition 1: a=ba = b. This implies a=1ba = 1 \cdot b, so aa is parallel to bb.
Condition 2: a=b|a| = |b|. This only means the magnitudes are equal. For example, a=(1,0)a = (1, 0) and b=(0,1)b = (0, 1) have the same magnitude but are not parallel.
Condition 3: aa and bb have opposite directions. This implies a=kba = -k \cdot b for some k>0k > 0. Therefore aa is parallel to bb.
Condition 4: a=0|a| = 0 or b=0|b| = 0. If a=0|a| = 0, then a=(0,0)a = (0, 0). If b=0|b| = 0, then b=(0,0)b = (0, 0). If a=0a = 0 and bb is any vector, then a=0ba = 0 \cdot b so aa and bb are parallel. Similarly, if b=0b=0 and aa is any vector, then b=0ab = 0\cdot a so bb and aa are parallel. If both aa and bb are the zero vector, they are parallel since a=1ba = 1 \cdot b.
Condition 5: aa and bb are unit vectors. This only means a=1|a| = 1 and b=1|b| = 1. Like condition 2, they can have different directions. For example, a=(1,0)a=(1,0) and b=(0,1)b=(0,1) are unit vectors, but are not parallel.
The conditions that ensure aa and bb are parallel are 1, 3, and
4.

3. Final Answer

134

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