We need to find the size of angle $k$ in the given figure. The figure shows a triangle with an external angle of $244^\circ$. The other two angles adjacent to the external angle are $29^\circ$ and $35^\circ$.

GeometryTriangleAnglesExterior AngleAngle Sum Property
2025/6/3

1. Problem Description

We need to find the size of angle kk in the given figure. The figure shows a triangle with an external angle of 244244^\circ. The other two angles adjacent to the external angle are 2929^\circ and 3535^\circ.

2. Solution Steps

First, we need to find the interior angles of the triangle at the vertices where the 2929^\circ and 3535^\circ angles are given. Let's call these angles aa and bb respectively.
Since the external angle is 244244^\circ, the interior angle adjacent to it is 360244=116360^\circ - 244^\circ = 116^\circ.
The sum of angles around a point is 360360^\circ, so we can determine the interior angles aa and bb.
a=18029=151a = 180^\circ - 29^\circ = 151^\circ is incorrect.
The angles 2929^\circ and 3535^\circ are angles exterior to two other interior angles. Let the angles adjacent to 2929^\circ and 3535^\circ be xx and yy. Then x+y=116x + y = 116^\circ, where 116116^\circ is the angle exterior to the 244244^\circ angle. We also have the following equations:
a=18029a = 180^\circ - 29^\circ
b=18035b = 180^\circ - 35^\circ
We know that the sum of the angles x,29x, 29^\circ and y,35y, 35^\circ are on a straight line that form an external angle of 244244^\circ. Thus, the angle on that vertex can also be expressed as 360244=116360^\circ - 244^\circ = 116^\circ.
So the three angles adjacent to the external angles 2929^\circ, 3535^\circ, and 244244^\circ sum to 116116^\circ.
To find angle kk, we need to find the remaining two angles of the large triangle.
The two given angles are:
a=18029(360244)=18029116=35a = 180^\circ - 29^\circ - (360^\circ - 244^\circ) = 180^\circ - 29^\circ - 116^\circ = 35^\circ
b=18035(360244)=18035116=29b = 180^\circ - 35^\circ - (360^\circ - 244^\circ) = 180^\circ - 35^\circ - 116^\circ = 29^\circ
So, we have interior angles of 2929^\circ and 3535^\circ at the bottom corners of the large triangle. Since the sum of angles in a triangle is 180180^\circ, we can write:
k+29+35=180k + 29^\circ + 35^\circ = 180^\circ
k+64=180k + 64^\circ = 180^\circ
k=18064k = 180^\circ - 64^\circ
k=116k = 116^\circ

3. Final Answer

116

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