Question 28: The probability that a seed planted will germinate is 0.75. If 3 of such seeds are planted, what is the probability that all the seeds will germinate? Question 29: The volume of a cone of height 18 cm is 8,316 $cm^3$. Find the base radius of the cone. Take $\pi = \frac{22}{7}$.

1. Problem Description

Question 28: The probability that a seed planted will germinate is 0.

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5. If 3 of such seeds are planted, what is the probability that all the seeds will germinate?

Question 29: The volume of a cone of height 18 cm is 8,316 $cm^3$. Find the base radius of the cone. Take $\pi = \frac{22}{7}$.

2. Solution Steps

Question 28:

The probability that all three seeds germinate is the product of the probability that each seed germinates.

Probability of one seed germinating = 0.75

Probability of three seeds germinating = $0.75 \times 0.75 \times 0.75 = (0.75)^3 = 0.421875$

Rounding to three decimal places, the probability is 0.

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Question 29:

The volume of a cone is given by the formula:

$V = \frac{1}{3} \pi r^2 h$, where V is the volume, r is the radius, and h is the height.

We are given V = 8316 $cm^3$, h = 18 cm, and $\pi = \frac{22}{7}$. We need to find r.

$8316 = \frac{1}{3} \times \frac{22}{7} \times r^2 \times 18$

$8316 = \frac{22}{7} \times r^2 \times 6$

$8316 = \frac{132}{7} r^2$

$r^2 = \frac{8316 \times 7}{132}$

$r^2 = \frac{58212}{132}$

$r^2 = 441$

$r = \sqrt{441}$

$r = 21$ cm

3. Final Answer

Question 28: D. 0.422

Question 29: A. 21 cm