Given vectors $\vec{a} = (1, x)$ and $\vec{b} = (2, -4)$, find the value of $x$ if $\vec{a}$ is parallel to $\vec{b}$.

AlgebraVectorsLinear AlgebraParallel Vectors
2025/3/27

1. Problem Description

Given vectors a=(1,x)\vec{a} = (1, x) and b=(2,4)\vec{b} = (2, -4), find the value of xx if a\vec{a} is parallel to b\vec{b}.

2. Solution Steps

If two vectors a=(a1,a2)\vec{a} = (a_1, a_2) and b=(b1,b2)\vec{b} = (b_1, b_2) are parallel, then their components are proportional, i.e.,
a1b1=a2b2\frac{a_1}{b_1} = \frac{a_2}{b_2}.
In our case, a=(1,x)\vec{a} = (1, x) and b=(2,4)\vec{b} = (2, -4). Therefore,
12=x4\frac{1}{2} = \frac{x}{-4}.
To solve for xx, we can multiply both sides of the equation by 4-4:
x=12×(4)x = \frac{1}{2} \times (-4)
x=2x = -2

3. Final Answer

The value of xx is 2-2. So the correct option is A.

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