The problem asks to convert the given 2-byte binary number, $1000111001110011$, into its hexadecimal representation by grouping the bits into groups of 4.

1. Problem Description

The problem asks to convert the given 2-byte binary number, $1000111001110011$, into its hexadecimal representation by grouping the bits into groups of

4.

2. Solution Steps

First, we group the binary number into groups of 4 bits, starting from the rightmost bit:

$1000 \ 1110 \ 0111 \ 0011$

Next, we convert each 4-bit group into its hexadecimal equivalent. Recall that:

$0000 = 0$

$0001 = 1$

$0010 = 2$

$0011 = 3$

$0100 = 4$

$0101 = 5$

$0110 = 6$

$0111 = 7$

$1000 = 8$

$1001 = 9$

$1010 = A$

$1011 = B$

$1100 = C$

$1101 = D$

$1110 = E$

$1111 = F$

Using the conversion table:

$1000 = 8$

$1110 = E$

$0111 = 7$

$0011 = 3$

Thus, $1000 \ 1110 \ 0111 \ 0011$ in binary is equivalent to $8E73$ in hexadecimal.

3. Final Answer

The hexadecimal equivalent of the binary number $1000111001110011$ is $8E73$.