Given points $A(-1, -3)$ and $B(0, -1)$, and vector $\vec{a} = (2, y)$. Also, $\vec{AB} // \vec{a}$. Find the value of $y$.

GeometryVectorsCoordinate GeometryParallel Vectors
2025/3/27

1. Problem Description

Given points A(1,3)A(-1, -3) and B(0,1)B(0, -1), and vector a=(2,y)\vec{a} = (2, y). Also, AB//a\vec{AB} // \vec{a}. Find the value of yy.

2. Solution Steps

First, we need to find the vector AB\vec{AB}.
AB=BA=(0(1),1(3))=(1,2)\vec{AB} = B - A = (0 - (-1), -1 - (-3)) = (1, 2)
Since AB//a\vec{AB} // \vec{a}, there exists a scalar kk such that AB=ka\vec{AB} = k\vec{a}. Thus,
(1,2)=k(2,y)=(2k,ky)(1, 2) = k(2, y) = (2k, ky)
From the first component, we have 1=2k1 = 2k, so k=12k = \frac{1}{2}.
From the second component, we have 2=ky2 = ky. Substituting k=12k = \frac{1}{2}, we get 2=12y2 = \frac{1}{2}y.
Solving for yy, we have y=22=4y = 2 \cdot 2 = 4.

3. Final Answer

The value of yy is

4. Answer: B. 4

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