The bunting flags are all isosceles triangles. We are given an isosceles triangle $PQR$ with angle $QPR = 76^{\circ}$. We need to find the size of angle $PRQ$.

1. Problem Description

The bunting flags are all isosceles triangles. We are given an isosceles triangle $PQR$ with angle $QPR = 76^{\circ}$. We need to find the size of angle $PRQ$.

2. Solution Steps

Since triangle $PQR$ is an isosceles triangle with $PR = QR$, the angles opposite these sides are equal, i.e., $angle PQR = angle QPR$. Therefore, $angle PQR = 76^{\circ}$.

The sum of the angles in a triangle is $180^{\circ}$.

Therefore, we have

$angle PQR + angle QPR + angle PRQ = 180^{\circ}$.

Substituting the known values, we have

$76^{\circ} + 76^{\circ} + angle PRQ = 180^{\circ}$.

$152^{\circ} + angle PRQ = 180^{\circ}$.

$angle PRQ = 180^{\circ} - 152^{\circ}$.

$angle PRQ = 28^{\circ}$.

3. Final Answer

The size of angle $PRQ$ is $28^{\circ}$.