The problem asks to find the slope and $y$-intercept of the line shown in the graph and then write the equation of the line.

AlgebraLinear EquationsSlopeY-interceptCoordinate Geometry
2025/3/6

1. Problem Description

The problem asks to find the slope and yy-intercept of the line shown in the graph and then write the equation of the line.

2. Solution Steps

First, we need to find two points on the line. From the graph, we can identify two points as (0,2)(0, 2) and (4,4)(4, -4).
Next, we can find the slope of the line using the formula:
m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}
Plugging in the coordinates of the points, we get:
m=4240=64=32m = \frac{-4 - 2}{4 - 0} = \frac{-6}{4} = -\frac{3}{2}
The yy-intercept is the point where the line crosses the yy-axis, which is the value of yy when x=0x = 0. From the graph, we can see that the yy-intercept is 22. Thus, b=2b = 2.
Now we can write the equation of the line in slope-intercept form, which is:
y=mx+by = mx + b
Substituting the values of mm and bb, we have:
y=32x+2y = -\frac{3}{2}x + 2

3. Final Answer

Slope = 32-\frac{3}{2}
y=32x+2y = -\frac{3}{2}x + 2

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