The problem asks us to find the power set of the set $A = \{a, b\}$. The power set of a set is the set of all possible subsets, including the empty set and the set itself.

Discrete MathematicsSet TheoryPower SetSubsets
2025/3/27

1. Problem Description

The problem asks us to find the power set of the set A={a,b}A = \{a, b\}. The power set of a set is the set of all possible subsets, including the empty set and the set itself.

2. Solution Steps

The power set of a set AA, denoted by P(A)P(A), is the set of all subsets of AA.
If a set AA has nn elements, then the power set P(A)P(A) has 2n2^n elements. In our case, A={a,b}A = \{a, b\}, so n=2n = 2. Therefore, P(A)P(A) should have 22=42^2 = 4 elements.
The subsets of A={a,b}A = \{a, b\} are:
* The empty set: \emptyset
* The subsets with one element: {a}\{a\}, {b}\{b\}
* The subset with two elements: {a,b}\{a, b\}
Therefore, the power set of A={a,b}A = \{a, b\} is P(A)={,{a},{b},{a,b}}P(A) = \{\emptyset, \{a\}, \{b\}, \{a, b\}\}.

3. Final Answer

The power set of A={a,b}A = \{a, b\} is {,{a},{b},{a,b}}\{\emptyset, \{a\}, \{b\}, \{a, b\}\}. Therefore, the correct answer is b.

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