Given that $\alpha$ is an acute angle, determine the range of $2\alpha$. The options are: [A] First quadrant angle [B] Second quadrant angle [C] Positive angle less than $180^\circ$ [D] Positive angle no greater than a right angle

GeometryAnglesTrigonometryInequalitiesAngle Measurement
2025/6/14

1. Problem Description

Given that α\alpha is an acute angle, determine the range of 2α2\alpha. The options are:
[A] First quadrant angle
[B] Second quadrant angle
[C] Positive angle less than 180180^\circ
[D] Positive angle no greater than a right angle

2. Solution Steps

Since α\alpha is an acute angle, we have 0<α<900^\circ < \alpha < 90^\circ.
Multiplying the inequality by 2, we get 0<2α<1800^\circ < 2\alpha < 180^\circ.
Thus, 2α2\alpha is a positive angle less than 180180^\circ.
Also, since 0<2α<1800^\circ < 2\alpha < 180^\circ, 2α2\alpha can be in the first or second quadrant.
Option A: If 0<2α<900^\circ < 2\alpha < 90^\circ, then 2α2\alpha is in the first quadrant. This is possible.
Option B: If 90<2α<18090^\circ < 2\alpha < 180^\circ, then 2α2\alpha is in the second quadrant. This is also possible.
Option C: Since 0<2α<1800^\circ < 2\alpha < 180^\circ, 2α2\alpha is a positive angle less than 180180^\circ.
Option D: If 0<2α900^\circ < 2\alpha \le 90^\circ, then 2α2\alpha is a positive angle no greater than a right angle. However, 2α2\alpha can be greater than 9090^\circ, so this option is not always true.
Since 2α2\alpha can be in the first quadrant (0<2α<900 < 2\alpha < 90) or in the second quadrant (90<2α<18090 < 2\alpha < 180).
However, the range 0<2α<1800^\circ < 2\alpha < 180^\circ implies that it is a positive angle less than 180 degrees.

3. Final Answer

[C] 小于180度的正角
Positive angle less than 180180^\circ.

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