The problem asks to find the volume of water in a rectangular parallelepiped, given its dimensions: 1 meter, 20 cm, and 25 cm. It is also stated that $\frac{13}{25}$ of the parallelepiped is filled with water. We need to find the volume of water in liters.

1. Problem Description

The problem asks to find the volume of water in a rectangular parallelepiped, given its dimensions: 1 meter, 20 cm, and 25 cm. It is also stated that $\frac{13}{25}$ of the parallelepiped is filled with water. We need to find the volume of water in liters.

2. Solution Steps

First, we convert all the dimensions to centimeters:

1 meter = 100 cm.

So the dimensions of the parallelepiped are 100 cm, 20 cm, and 25 cm.

The volume of the parallelepiped is given by the product of its dimensions:

$V = l \times w \times h$

$V = 100 \times 20 \times 25 = 50000 \, \text{cm}^3$

The volume of water is $\frac{13}{25}$ of the total volume:

$V_{\text{water}} = \frac{13}{25} \times V$

$V_{\text{water}} = \frac{13}{25} \times 50000 = 13 \times 2000 = 26000 \, \text{cm}^3$

Since 1 liter is equal to 1000 cm$^3$, we convert the volume of water to liters:

$V_{\text{water (liters)}} = \frac{26000}{1000} = 26 \, \text{liters}$

3. Final Answer

The volume of water in the parallelepiped is 26 liters.