We are asked to find the size of angle $DAB$ in a quadrilateral $ABCD$. We are given that angle $ADC = 98^{\circ}$, angle $BCD = 90^{\circ}$ (right angle) and angle $ABC = 69^{\circ}$.

1. Problem Description

We are asked to find the size of angle $DAB$ in a quadrilateral $ABCD$. We are given that angle $ADC = 98^{\circ}$, angle $BCD = 90^{\circ}$ (right angle) and angle $ABC = 69^{\circ}$.

2. Solution Steps

The sum of the interior angles of a quadrilateral is $360^{\circ}$. Therefore, we have:

$angle DAB + angle ADC + angle DCB + angle CBA = 360^{\circ}$

We are given the measures of $angle ADC$, $angle DCB$ and $angle CBA$.

$angle ADC = 98^{\circ}$

$angle DCB = 90^{\circ}$

$angle CBA = 69^{\circ}$

Substituting these values into the equation, we get:

$angle DAB + 98^{\circ} + 90^{\circ} + 69^{\circ} = 360^{\circ}$

$angle DAB + 257^{\circ} = 360^{\circ}$

$angle DAB = 360^{\circ} - 257^{\circ}$

$angle DAB = 103^{\circ}$

3. Final Answer

The size of angle $DAB$ is $103^{\circ}$.