We need to evaluate the expression $(6 * 2^3 / 8) + 4 \pmod{3-5}$. This includes exponentiation, multiplication/division, addition, and the modulo operation.

1. Problem Description

We need to evaluate the expression $(6 * 2^3 / 8) + 4 \pmod{3-5}$. This includes exponentiation, multiplication/division, addition, and the modulo operation.

2. Solution Steps

First, calculate $2^3$:

$2^3 = 2*2*2 = 8$

Then calculate $6 * 2^3 / 8$:

$6 * 2^3 / 8 = 6 * 8 / 8 = 6 * 1 = 6$

Next, add 4:

$6 + 4 = 10$

Then calculate $3 - 5$:

$3 - 5 = -2$

Finally, calculate $10 \pmod{-2}$:

$10 \pmod{-2}$ means find the remainder when 10 is divided by -

2. Since $10 = (-2) * (-5) + 0$, the remainder is

0. Alternatively, we can say $x \pmod n$ is the unique integer $r$ such that $x = qn + r$ and $0 \le r < |n|$. In this case, since $n = -2$, we want $0 \le r < |-2| = 2$. Then $10 = (-5)*(-2) + 0$, and $0$ satisfies $0 \le r < 2$.

3. Final Answer

$0$