We need to solve four algebraic equations for $x$. The equations are: 9. $4x = x - (x - 2)$ 10. $7x = 3x - (x + 20)$ 11. $5x - 3(x - 1) = 39$ 12. $3x + 2(x - 5) = 15$

AlgebraLinear EquationsSolving Equations
2025/6/23

1. Problem Description

We need to solve four algebraic equations for xx. The equations are:

9. $4x = x - (x - 2)$

1

0. $7x = 3x - (x + 20)$

1

1. $5x - 3(x - 1) = 39$

1

2. $3x + 2(x - 5) = 15$

2. Solution Steps

Solving equation 9:
4x=x(x2)4x = x - (x - 2)
4x=xx+24x = x - x + 2
4x=24x = 2
x=24x = \frac{2}{4}
x=12x = \frac{1}{2}
Solving equation 10:
7x=3x(x+20)7x = 3x - (x + 20)
7x=3xx207x = 3x - x - 20
7x=2x207x = 2x - 20
7x2x=207x - 2x = -20
5x=205x = -20
x=205x = \frac{-20}{5}
x=4x = -4
Solving equation 11:
5x3(x1)=395x - 3(x - 1) = 39
5x3x+3=395x - 3x + 3 = 39
2x+3=392x + 3 = 39
2x=3932x = 39 - 3
2x=362x = 36
x=362x = \frac{36}{2}
x=18x = 18
Solving equation 12:
3x+2(x5)=153x + 2(x - 5) = 15
3x+2x10=153x + 2x - 10 = 15
5x10=155x - 10 = 15
5x=15+105x = 15 + 10
5x=255x = 25
x=255x = \frac{25}{5}
x=5x = 5

3. Final Answer

The solutions are:

9. $x = \frac{1}{2}$

1

0. $x = -4$

1

1. $x = 18$

1

2. $x = 5$

Related problems in "Algebra"