The problem provides the volume of an acetic acid solution in a bottle ($500 \, \text{cm}^3$), the density of the solution ($1.04 \, \text{g/cm}^3$), and the mass of acetic acid in the solution ($26 \, \text{g}$). The problem asks us to: (i) Calculate the mass of the acetic acid solution in the bottle. (ii) Calculate the mass percentage of acetic acid in the solution.

1. Problem Description

The problem provides the volume of an acetic acid solution in a bottle ($500 \, \text{cm}^3$), the density of the solution ($1.04 \, \text{g/cm}^3$), and the mass of acetic acid in the solution ($26 \, \text{g}$). The problem asks us to:

(i) Calculate the mass of the acetic acid solution in the bottle.

(ii) Calculate the mass percentage of acetic acid in the solution.

2. Solution Steps

(i) To find the mass of the acetic acid solution, we use the formula:

$Density = \frac{Mass}{Volume}$.

We are given the density ($1.04 \, \text{g/cm}^3$) and the volume ($500 \, \text{cm}^3$). Rearranging the formula, we get:

$Mass = Density \times Volume$

$Mass = 1.04 \, \text{g/cm}^3 \times 500 \, \text{cm}^3 = 520 \, \text{g}$

Therefore, the mass of the acetic acid solution is $520 \, \text{g}$.

(ii) To find the mass percentage of acetic acid in the solution, we use the formula:

$Mass \, percentage = \frac{Mass \, of \, acetic \, acid}{Mass \, of \, solution} \times 100$

We are given the mass of acetic acid ($26 \, \text{g}$) and we calculated the mass of the solution ($520 \, \text{g}$) in part (i). Therefore,

$Mass \, percentage = \frac{26 \, \text{g}}{520 \, \text{g}} \times 100 = \frac{2600}{520} = 5$

Therefore, the mass percentage of acetic acid in the solution is $5\%$.

3. Final Answer

(i) The mass of the acetic acid solution is $520 \, \text{g}$.

(ii) The mass percentage of acetic acid in the solution is $5\%$.