We are asked to solve problem number 28 from the image, which is to find the value of $x$ in the equation $\frac{4}{x+1} = \frac{7}{3x-2}$.

1. Problem Description

We are asked to solve problem number 28 from the image, which is to find the value of $x$ in the equation $\frac{4}{x+1} = \frac{7}{3x-2}$.

2. Solution Steps

To solve the equation $\frac{4}{x+1} = \frac{7}{3x-2}$, we can cross-multiply:

$4(3x-2) = 7(x+1)$

Expanding both sides of the equation, we have:

$12x - 8 = 7x + 7$

Now, we subtract $7x$ from both sides:

$12x - 7x - 8 = 7x - 7x + 7$

$5x - 8 = 7$

Next, we add 8 to both sides:

$5x - 8 + 8 = 7 + 8$

$5x = 15$

Finally, we divide both sides by 5:

$\frac{5x}{5} = \frac{15}{5}$

$x = 3$

3. Final Answer

$x = 3$