We need to solve the following equations for $x$: 28. $\frac{4}{x+1} = \frac{7}{3x-2}$ 29. $\frac{x+1}{2} + \frac{x-1}{3} = \frac{1}{6}$ 30. $\frac{1}{3}(x+2) = \frac{1}{5}(3x+2)$ 31. $\frac{1}{2}(x-1) - \frac{1}{6}(x+1) = 0$ 32. $\frac{1}{4}(x+5) - \frac{2x}{3} = 0$ 33. $\frac{4}{x} + 2 = 3$ 34. $\frac{6}{x} - 3 = 7$ 35. $\frac{9}{x} - 7 = 1$ 36. $-2 = 1 + \frac{3}{x}$ 37. $4 - \frac{4}{x} = 0$ 38. $5 - \frac{6}{x} = -1$ 39. $7 - \frac{3}{2x} = 1$ 40. $4 + \frac{5}{3x} = -1$ 41. $\frac{9}{2x} - 5 = 0$ 42. $\frac{x-1}{5} - \frac{x-1}{3} = 0$ 43. $\frac{x-1}{4} - \frac{2x-3}{5} = \frac{1}{20}$ 44. $\frac{4}{1-x} = \frac{3}{1+x}$ 45. $\frac{x+1}{4} - \frac{x}{3} = \frac{1}{12}$ 46. $\frac{2x+1}{8} - \frac{x-1}{3} = \frac{5}{24}$
2025/6/25
1. Problem Description
We need to solve the following equations for :
2
8. $\frac{4}{x+1} = \frac{7}{3x-2}$
2
9. $\frac{x+1}{2} + \frac{x-1}{3} = \frac{1}{6}$
3
0. $\frac{1}{3}(x+2) = \frac{1}{5}(3x+2)$
3
1. $\frac{1}{2}(x-1) - \frac{1}{6}(x+1) = 0$
3
2. $\frac{1}{4}(x+5) - \frac{2x}{3} = 0$
3
3. $\frac{4}{x} + 2 = 3$
3
4. $\frac{6}{x} - 3 = 7$
3
5. $\frac{9}{x} - 7 = 1$
3
6. $-2 = 1 + \frac{3}{x}$
3
7. $4 - \frac{4}{x} = 0$
3
8. $5 - \frac{6}{x} = -1$
3
9. $7 - \frac{3}{2x} = 1$
4
0. $4 + \frac{5}{3x} = -1$
4
1. $\frac{9}{2x} - 5 = 0$
4
2. $\frac{x-1}{5} - \frac{x-1}{3} = 0$
4
3. $\frac{x-1}{4} - \frac{2x-3}{5} = \frac{1}{20}$
4
4. $\frac{4}{1-x} = \frac{3}{1+x}$
4
5. $\frac{x+1}{4} - \frac{x}{3} = \frac{1}{12}$
4
6. $\frac{2x+1}{8} - \frac{x-1}{3} = \frac{5}{24}$
2. Solution Steps
2
8. $\frac{4}{x+1} = \frac{7}{3x-2}$
2
9. $\frac{x+1}{2} + \frac{x-1}{3} = \frac{1}{6}$
Multiply by 6:
3
0. $\frac{1}{3}(x+2) = \frac{1}{5}(3x+2)$
Multiply by 15:
3
1. $\frac{1}{2}(x-1) - \frac{1}{6}(x+1) = 0$
Multiply by 6:
3
2. $\frac{1}{4}(x+5) - \frac{2x}{3} = 0$
Multiply by 12:
3
3. $\frac{4}{x} + 2 = 3$
3
4. $\frac{6}{x} - 3 = 7$
3
5. $\frac{9}{x} - 7 = 1$
3
6. $-2 = 1 + \frac{3}{x}$
3
7. $4 - \frac{4}{x} = 0$
3
8. $5 - \frac{6}{x} = -1$
3
9. $7 - \frac{3}{2x} = 1$
4
0. $4 + \frac{5}{3x} = -1$
4
1. $\frac{9}{2x} - 5 = 0$
4
2. $\frac{x-1}{5} - \frac{x-1}{3} = 0$
4
3. $\frac{x-1}{4} - \frac{2x-3}{5} = \frac{1}{20}$
Multiply by 20:
4
4. $\frac{4}{1-x} = \frac{3}{1+x}$
4
5. $\frac{x+1}{4} - \frac{x}{3} = \frac{1}{12}$
Multiply by 12:
4
6. $\frac{2x+1}{8} - \frac{x-1}{3} = \frac{5}{24}$
Multiply by 24:
3. Final Answer
2
8. $x = 3$
2
9. $x = 0$
3
0. $x = 1$
3
1. $x = 2$
3
2. $x = 3$
3
3. $x = 4$
3
4. $x = \frac{3}{5}$
3
5. $x = \frac{9}{8}$
3
6. $x = -1$
3
7. $x = 1$
3
8. $x = 1$
3
9. $x = \frac{1}{4}$
4
0. $x = -\frac{1}{3}$
4
1. $x = \frac{9}{10}$
4
2. $x = 1$
4
3. $x = 2$
4
4. $x = -\frac{1}{7}$
4
5. $x = 2$
4