Find the equation of the plane passing through the point $D(1, 0, 2)$ and parallel to the $yz$-plane.

Geometry3D GeometryPlanesCoordinate Geometry
2025/6/28

1. Problem Description

Find the equation of the plane passing through the point D(1,0,2)D(1, 0, 2) and parallel to the yzyz-plane.

2. Solution Steps

The yzyz-plane is defined by the equation x=0x = 0. A plane parallel to the yzyz-plane will have the form x=cx = c for some constant cc.
Since the plane passes through the point D(1,0,2)D(1, 0, 2), we can substitute the coordinates of this point into the equation of the plane x=cx=c.
Substituting x=1x=1 into x=cx=c gives c=1c = 1.
Therefore, the equation of the plane is x=1x = 1.

3. Final Answer

x=1x = 1

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