The problem asks to find the equation of a plane passing through the point $D(1,0,2)$. The expression $(Z0/16)$ might indicate the date or the version of the problem.

1. Problem Description

The problem asks to find the equation of a plane passing through the point $D(1,0,2)$. The expression $(Z0/16)$ might indicate the date or the version of the problem.

2. Solution Steps

The given information is a single point $D(1,0,2)$. To define a plane, we typically need either three points, a point and a normal vector, or other constraints. Since only one point is given, it's impossible to uniquely determine the equation of a plane. We can only find the general form of the equation of a plane that passes through the point $(1,0,2)$.

The general equation of a plane is given by:

$ax + by + cz + d = 0$

Since the point $D(1,0,2)$ lies on the plane, it must satisfy the equation:

$a(1) + b(0) + c(2) + d = 0$

$a + 2c + d = 0$

Therefore, $d = -a - 2c$

Substitute this back into the general equation of the plane:

$ax + by + cz - a - 2c = 0$

$a(x-1) + by + c(z-2) = 0$

This is the general form of the plane that passes through the point $D(1,0,2)$. Without additional information, $a, b,$ and $c$ can be any real numbers (not all zero).

3. Final Answer

The equation of the plane passing through the point $D(1,0,2)$ is given by $a(x-1) + by + c(z-2) = 0$, where $a, b,$ and $c$ are not all zero. This represents a family of planes that pass through the point (1,0,2).