We are given a right triangle with hypotenuse of length 6 km, an angle of 30 degrees, and the opposite side to this angle is $x = 3$ km. We need to find the length of the adjacent side (adj) to the 30 degree angle to 3 decimal places.

GeometryTrigonometryRight TrianglesCosineApproximation
2025/3/10

1. Problem Description

We are given a right triangle with hypotenuse of length 6 km, an angle of 30 degrees, and the opposite side to this angle is x=3x = 3 km. We need to find the length of the adjacent side (adj) to the 30 degree angle to 3 decimal places.

2. Solution Steps

Let the length of the adjacent side be denoted by aa.
We can use the cosine function:
cos(θ)=adjacenthypotenusecos(\theta) = \frac{adjacent}{hypotenuse}
cos(30)=a6cos(30^{\circ}) = \frac{a}{6}
a=6cos(30)a = 6 * cos(30^{\circ})
We know that cos(30)=32cos(30^{\circ}) = \frac{\sqrt{3}}{2}.
So, a=632=33a = 6 * \frac{\sqrt{3}}{2} = 3\sqrt{3}.
We want to approximate aa to 3 decimal places.
We know 31.73205080757\sqrt{3} \approx 1.73205080757.
a=3331.732050807575.19615242271a = 3 * \sqrt{3} \approx 3 * 1.73205080757 \approx 5.19615242271.
Rounding to 3 decimal places, we get a5.196a \approx 5.196.

3. Final Answer

5.1965.196

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