The problem asks to find the perimeter and area of a rectangle in $cm$. The given rectangle has a length of $8 m$ and a width of $5 m$.

1. Problem Description

The problem asks to find the perimeter and area of a rectangle in $cm$. The given rectangle has a length of $8 m$ and a width of $5 m$.

2. Solution Steps

First, we need to convert the dimensions from meters to centimeters. Since $1 m = 100 cm$, we have:

Length $= 8 m = 8 \times 100 cm = 800 cm$

Width $= 5 m = 5 \times 100 cm = 500 cm$

Next, we calculate the perimeter of the rectangle. The formula for the perimeter $P$ of a rectangle is:

$P = 2 \times (length + width)$

Substituting the values, we get:

$P = 2 \times (800 cm + 500 cm) = 2 \times 1300 cm = 2600 cm$

Then, we calculate the area of the rectangle. The formula for the area $A$ of a rectangle is:

$A = length \times width$

Substituting the values, we get:

$A = 800 cm \times 500 cm = 400000 cm^2$

3. Final Answer

Perimeter $= 2600 cm$

Area $= 400000 cm^2$