We are given the equation $log(2-3x) + 15 = 0$ and we need to solve for $x$.

1. Problem Description

We are given the equation $log(2-3x) + 15 = 0$ and we need to solve for $x$.

2. Solution Steps

First, we isolate the logarithmic term by subtracting 15 from both sides of the equation:

$log(2-3x) = -15$

We assume the logarithm is base

1

0. To remove the logarithm, we raise 10 to the power of both sides:

$10^{log(2-3x)} = 10^{-15}$

$2-3x = 10^{-15}$

Now, we want to isolate $x$. Subtract 2 from both sides:

$-3x = 10^{-15} - 2$

Divide both sides by -3:

$x = \frac{10^{-15} - 2}{-3}$

$x = \frac{2 - 10^{-15}}{3}$

3. Final Answer

$x = \frac{2 - 10^{-15}}{3}$