We are given a system of two linear equations with two variables, $x$ and $y$: $7x - 6y = 30$ $2x + 6y = 24$ Our goal is to find the values of $x$ and $y$ that satisfy both equations.

AlgebraLinear EquationsSystem of EquationsElimination Method
2025/6/5

1. Problem Description

We are given a system of two linear equations with two variables, xx and yy:
7x6y=307x - 6y = 30
2x+6y=242x + 6y = 24
Our goal is to find the values of xx and yy that satisfy both equations.

2. Solution Steps

We can solve this system of equations using the elimination method. Notice that the coefficients of yy in the two equations are 6-6 and 66, so adding the two equations will eliminate yy.
Adding the two equations gives:
(7x6y)+(2x+6y)=30+24(7x - 6y) + (2x + 6y) = 30 + 24
7x+2x6y+6y=547x + 2x - 6y + 6y = 54
9x=549x = 54
Now, we can solve for xx by dividing both sides by 9:
x=549x = \frac{54}{9}
x=6x = 6
Now that we have the value of xx, we can substitute it into either equation to solve for yy. Let's use the second equation:
2x+6y=242x + 6y = 24
2(6)+6y=242(6) + 6y = 24
12+6y=2412 + 6y = 24
Subtract 12 from both sides:
6y=24126y = 24 - 12
6y=126y = 12
Divide both sides by 6:
y=126y = \frac{12}{6}
y=2y = 2
Therefore, the solution to the system of equations is x=6x = 6 and y=2y = 2.

3. Final Answer

x=6,y=2x = 6, y = 2