We are given the equation $\sin^{-1} x + \cos^{-1} x = \frac{\pi}{2}$ and asked to find the value of $x$.

AlgebraTrigonometryInverse Trigonometric FunctionsEquationsDomain and Range
2025/7/31

1. Problem Description

We are given the equation sin1x+cos1x=π2\sin^{-1} x + \cos^{-1} x = \frac{\pi}{2} and asked to find the value of xx.

2. Solution Steps

The identity that relates the inverse sine and inverse cosine functions is:
sin1x+cos1x=π2\sin^{-1} x + \cos^{-1} x = \frac{\pi}{2}
This identity holds true for all xx in the domain of both sin1x\sin^{-1} x and cos1x\cos^{-1} x, which is [1,1][-1, 1].
Since the equation given in the problem is the same as the identity, any xx value in the interval [1,1][-1, 1] will satisfy the equation.

3. Final Answer

The solution is any xx in the interval [1,1][-1, 1].
x[1,1]x \in [-1, 1]