The problem is to solve the linear equation $2(x - 2) - (x - 1) = 2x - 2$ for $x$.

AlgebraLinear EquationsEquation SolvingAlgebraic Manipulation
2025/6/5

1. Problem Description

The problem is to solve the linear equation 2(x2)(x1)=2x22(x - 2) - (x - 1) = 2x - 2 for xx.

2. Solution Steps

First, distribute the 22 in 2(x2)2(x - 2):
2(x2)=2x42(x - 2) = 2x - 4
Next, distribute the negative sign in (x1)-(x - 1):
(x1)=x+1-(x - 1) = -x + 1
Now, substitute these back into the original equation:
2x4x+1=2x22x - 4 - x + 1 = 2x - 2
Combine like terms on the left side:
2xx4+1=x32x - x - 4 + 1 = x - 3
So the equation becomes:
x3=2x2x - 3 = 2x - 2
Subtract xx from both sides of the equation:
x3x=2x2xx - 3 - x = 2x - 2 - x
3=x2-3 = x - 2
Add 22 to both sides of the equation:
3+2=x2+2-3 + 2 = x - 2 + 2
1=x-1 = x
Thus, x=1x = -1.

3. Final Answer

x=1x = -1

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