A binary operation $*$ is defined on the set of real numbers $R$ by $a * b = 4a^2b$. We need to evaluate $\frac{1}{4} * \frac{1}{2}$.

AlgebraBinary OperationReal NumbersAlgebraic Manipulation
2025/7/6

1. Problem Description

A binary operation * is defined on the set of real numbers RR by ab=4a2ba * b = 4a^2b. We need to evaluate 1412\frac{1}{4} * \frac{1}{2}.

2. Solution Steps

Given the definition of the binary operation *, we have:
ab=4a2ba * b = 4a^2b
We need to evaluate 1412\frac{1}{4} * \frac{1}{2}. Substituting a=14a = \frac{1}{4} and b=12b = \frac{1}{2} into the definition of the operation, we get:
1412=4(14)2(12)\frac{1}{4} * \frac{1}{2} = 4 \left(\frac{1}{4}\right)^2 \left(\frac{1}{2}\right)
1412=4(116)(12)\frac{1}{4} * \frac{1}{2} = 4 \left(\frac{1}{16}\right) \left(\frac{1}{2}\right)
1412=4(132)\frac{1}{4} * \frac{1}{2} = 4 \left(\frac{1}{32}\right)
1412=432\frac{1}{4} * \frac{1}{2} = \frac{4}{32}
1412=18\frac{1}{4} * \frac{1}{2} = \frac{1}{8}

3. Final Answer

18\frac{1}{8}

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