The image contains several math problems. I will solve problem number 12. The problem asks to find the length of side $x$ in the given triangle in simplest radical form with a rational denominator. The triangle is a right triangle with a 30-60-90 angles, and one side with length 4.

GeometryTrianglesRight Triangles30-60-90 TrianglesTrigonometrySineSpecial Right TrianglesRadicals
2025/4/1

1. Problem Description

The image contains several math problems. I will solve problem number
1

2. The problem asks to find the length of side $x$ in the given triangle in simplest radical form with a rational denominator. The triangle is a right triangle with a 30-60-90 angles, and one side with length

4.

2. Solution Steps

Let's denote the sides of the triangle as follows:
- Hypotenuse: c=4c = 4
- Side opposite to 30-degree angle: xx
- Side opposite to 60-degree angle: unknown
Since it's a 30-60-90 triangle, we know the ratios of the sides are 1:3:21:\sqrt{3}:2.
The hypotenuse is 2x2x, where xx is the side opposite the 30-degree angle. Therefore, 2x=42x=4, implying x=2x=2.
However, this is not consistent with the problem where xx is supposed to be adjacent to 60 degrees. Let's consider the other relationship.
The hypotenuse is

4. The side adjacent to the 60-degree angle which is $x$.

cos(60)=x4\cos(60^\circ) = \frac{x}{4}
Since cos(60)=12\cos(60^\circ) = \frac{1}{2}, we have 12=x4\frac{1}{2} = \frac{x}{4}.
Solving for xx, we get x=2x = 2.
Let's consider that x is the adjacent side to 30 degrees.
cos(30)=x4\cos(30^\circ) = \frac{x}{4}
Since cos(30)=32\cos(30^\circ) = \frac{\sqrt{3}}{2}, we have 32=x4\frac{\sqrt{3}}{2} = \frac{x}{4}.
Solving for xx, we get x=23x = 2\sqrt{3}. Since the problem shows xx is opposite the 30-degree angle in a right triangle with hypotenuse 4, the correct solution is
sin(30)=x4\sin(30^\circ) = \frac{x}{4}.
Since sin(30)=12\sin(30^\circ) = \frac{1}{2}, we have 12=x4\frac{1}{2} = \frac{x}{4}.
Solving for xx, we get x=2x = 2.
However, the figure shown in question 12 does not show that. Thus let's assume the 60 degree angle.
sin(60)=opphyp=opp4\sin(60^\circ) = \frac{opp}{hyp} = \frac{opp}{4}
opp=4sin(60)=432=23opp = 4\sin(60^\circ) = 4 * \frac{\sqrt{3}}{2} = 2\sqrt{3}. Since it shows a 30 60 90, this looks like xx is opposite the 30 degree angle.

3. Final Answer

232\sqrt{3}

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