The problem asks us to find the number of times we would expect a spinner to land on a number less than 7 if it is spun 250 times. The spinner has 10 equally likely outcomes labeled 1 through 10.

1. Problem Description

The problem asks us to find the number of times we would expect a spinner to land on a number less than 7 if it is spun 250 times. The spinner has 10 equally likely outcomes labeled 1 through

1

0.

2. Solution Steps

First, we need to determine the probability of the spinner landing on a number less than 7 in a single spin. The numbers less than 7 are 1, 2, 3, 4, 5, and

6. There are 6 such numbers.

Since there are 10 equally likely outcomes, the probability of landing on a number less than 7 is $\frac{6}{10}$ or $\frac{3}{5}$.

Next, we need to find the expected number of times the spinner will land on a number less than 7 when spun 250 times. This is calculated by multiplying the probability of landing on a number less than 7 in a single spin by the total number of spins:

$\text{Expected Number} = \text{Probability} \times \text{Number of Spins}$

$\text{Expected Number} = \frac{3}{5} \times 250$

$\text{Expected Number} = 3 \times 50$

$\text{Expected Number} = 150$

3. Final Answer

$150$