We are given that the area of the triangular faces of a prism is $348 \text{ cm}^2$. Also, $x + 4x + 5x = 348$. We need to find the value of $x$, which represents the length of the prism.

AlgebraLinear EquationsSolving EquationsSystem of Equations
2025/7/15

1. Problem Description

We are given that the area of the triangular faces of a prism is 348 cm2348 \text{ cm}^2. Also, x+4x+5x=348x + 4x + 5x = 348. We need to find the value of xx, which represents the length of the prism.

2. Solution Steps

The given equation is x+4x+5x=348x + 4x + 5x = 348.
Combine the terms on the left side:
1x+4x+5x=(1+4+5)x=10x1x + 4x + 5x = (1+4+5)x = 10x.
So we have 10x=34810x = 348.
To solve for xx, divide both sides by 1010:
x=34810=34.8x = \frac{348}{10} = 34.8
The value of xx is 34.8 cm34.8 \text{ cm}.
The student has written the equation x+4x+5x=348x+4x+5x=348.
Then combined the terms as 12x=34812x = 348.
So x=34812=29x=\frac{348}{12}=29.
3xy=73x - y = 7
5x+9=255x + 9 = 25. We are asked to find x+yx+y.
From 5x+9=255x+9=25, we can find xx:
5x=259=165x = 25-9=16
x=165=3.2x = \frac{16}{5} = 3.2
Substitute x=3.2x = 3.2 into 3xy=73x-y=7:
3(3.2)y=73(3.2) - y = 7
9.6y=79.6 - y = 7
y=9.67y = 9.6 - 7
y=2.6y = 2.6
Now find x+yx+y:
x+y=3.2+2.6=5.8x+y = 3.2 + 2.6 = 5.8

3. Final Answer

The length of the prism is 29 cm.
The value of x+y=5.8x+y = 5.8.