We are presented with three separate math problems. Let's define $x$ as the unknown number for each problem. Problem 2: If we multiply a number by 6 and add 1, we get the same answer as when we add 5 to the number and then treble the result. Find this number. Problem 3: If we add 3 to a number and quadruple the result, the answer is 36. What is the number? Problem 4: If you add 5 to a number and then multiply the result by 4, you get the same answer as when you add 1 to the number and then multiply the result by 2. What is the number?

AlgebraLinear EquationsWord ProblemsEquation Solving
2025/7/16

1. Problem Description

We are presented with three separate math problems. Let's define xx as the unknown number for each problem.
Problem 2: If we multiply a number by 6 and add 1, we get the same answer as when we add 5 to the number and then treble the result. Find this number.
Problem 3: If we add 3 to a number and quadruple the result, the answer is
3

6. What is the number?

Problem 4: If you add 5 to a number and then multiply the result by 4, you get the same answer as when you add 1 to the number and then multiply the result by

2. What is the number?

2. Solution Steps

Problem 2:
* Translate the word problem into an equation: 6x+1=3(x+5)6x + 1 = 3(x + 5)
* Expand the right side: 6x+1=3x+156x + 1 = 3x + 15
* Subtract 3x3x from both sides: 3x+1=153x + 1 = 15
* Subtract 1 from both sides: 3x=143x = 14
* Divide both sides by 3: x=143x = \frac{14}{3}
Problem 3:
* Translate the word problem into an equation: 4(x+3)=364(x + 3) = 36
* Expand the left side: 4x+12=364x + 12 = 36
* Subtract 12 from both sides: 4x=244x = 24
* Divide both sides by 4: x=6x = 6
Problem 4:
* Translate the word problem into an equation: 4(x+5)=2(x+1)4(x + 5) = 2(x + 1)
* Expand both sides: 4x+20=2x+24x + 20 = 2x + 2
* Subtract 2x2x from both sides: 2x+20=22x + 20 = 2
* Subtract 20 from both sides: 2x=182x = -18
* Divide both sides by 2: x=9x = -9

3. Final Answer

Problem 2: 143\frac{14}{3}
Problem 3: 66
Problem 4: 9-9