The problem asks to find the value of $p$ in the given triangle where the exterior angles are $3p$, $3p$, and $6p$.

1. Problem Description

The problem asks to find the value of $p$ in the given triangle where the exterior angles are $3p$, $3p$, and $6p$.

2. Solution Steps

The sum of the exterior angles of any polygon is $360$ degrees. In this case, the polygon is a triangle. Thus, the sum of the exterior angles of the given triangle is $3p + 3p + 6p = 360$.

Simplifying the left side, we have $12p = 360$.

Dividing both sides by $12$, we get

$p = \frac{360}{12} = 30$.

3. Final Answer

$p = 30$