The image shows an L-shaped figure. The dimensions of the outer rectangle are given as $(2x+5)$ meters and $(x+1)$ meters. The problem is to find something about the L-shaped figure, but without further context/question, I can only provide the area or the perimeter. I'll assume we're supposed to find the area of the outer rectangle.

1. Problem Description

The image shows an L-shaped figure. The dimensions of the outer rectangle are given as $(2x+5)$ meters and $(x+1)$ meters. The problem is to find something about the L-shaped figure, but without further context/question, I can only provide the area or the perimeter. I'll assume we're supposed to find the area of the outer rectangle.

2. Solution Steps

The area of a rectangle is given by the formula:

$Area = length \times width$

In this case, the length is $(2x+5)$ meters and the width is $(x+1)$ meters. Therefore, the area of the rectangle is:

$Area = (2x+5)(x+1)$

Expanding this expression:

$Area = 2x(x+1) + 5(x+1)$

$Area = 2x^2 + 2x + 5x + 5$

$Area = 2x^2 + 7x + 5$

3. Final Answer

The area of the outer rectangle is $(2x^2 + 7x + 5) \ m^2$.