The problem involves two parallel lines and a transversal that forms two triangles. We need to determine the relationship between angles $x$, $y$, and $z$.

GeometryParallel LinesTransversalAnglesTriangle PropertiesAlternate Interior AnglesAngle Sum of a Triangle
2025/7/16

1. Problem Description

The problem involves two parallel lines and a transversal that forms two triangles. We need to determine the relationship between angles xx, yy, and zz.

2. Solution Steps

Since lines PQPQ and RSRS are parallel, the angle at QQ (labeled xx) and the angle at RR (labeled yy) are alternate interior angles. These angles are therefore equal.
x=yx = y
Now consider triangle QZRQZR. The sum of the interior angles in a triangle is 180180^\circ. Therefore, in triangle QZRQZR, we have:
x+y+z=180x + y + z = 180^\circ
Since x=yx = y, we can substitute xx for yy in the equation above:
x+x+z=180x + x + z = 180^\circ
2x+z=1802x + z = 180^\circ
Therefore 2y+z=1802y + z = 180^\circ

3. Final Answer

The relationship is 2x+z=1802x + z = 180^\circ and x=yx=y. This is equivalent to 2y+z=1802y + z = 180^\circ.

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