The problem states that we have 3 types of animals: a horse, an elephant, and a chicken. The price of a horse is $Rs. 1$. The price of an elephant is $Rs. 5$. The price of a chicken is $Rs. 0.05$. We need to take 100 animals in total, and the total price should be $Rs. 100$. We need to find out how many of each animal we should take.

1. Problem Description

The problem states that we have 3 types of animals: a horse, an elephant, and a chicken. The price of a horse is $Rs. 1$. The price of an elephant is $Rs. 5$. The price of a chicken is $Rs. 0.05$. We need to take 100 animals in total, and the total price should be $Rs. 100$. We need to find out how many of each animal we should take.

2. Solution Steps

Let $x$ be the number of horses, $y$ be the number of elephants, and $z$ be the number of chickens. We can set up the following equations:

$x + y + z = 100$ (total number of animals)

$1x + 5y + 0.05z = 100$ (total cost)

We can multiply the second equation by 20 to eliminate the decimal:

$20x + 100y + z = 2000$

Now we have the following system of equations:

$x + y + z = 100$

$20x + 100y + z = 2000$

Subtract the first equation from the second equation:

$(20x + 100y + z) - (x + y + z) = 2000 - 100$

$19x + 99y = 1900$

We can rearrange the equation to solve for $x$:

$19x = 1900 - 99y$

$x = \frac{1900 - 99y}{19}$

$x = 100 - \frac{99y}{19}$

Since $x$ and $y$ must be integers, $99y$ must be divisible by

1

9. This means $y$ must be a multiple of

1

9. Let $y = 19k$, where $k$ is an integer.

Then $x = 100 - \frac{99(19k)}{19}$

$x = 100 - 99k$

Since $x$ and $y$ must be positive integers, we have:

$x > 0 \Rightarrow 100 - 99k > 0 \Rightarrow 99k < 100 \Rightarrow k < \frac{100}{99} \approx 1.01$

$y > 0 \Rightarrow 19k > 0 \Rightarrow k > 0$

Therefore, the only integer value for $k$ is

1. $k = 1$

$y = 19(1) = 19$

$x = 100 - 99(1) = 1$

Now we can find $z$:

$x + y + z = 100$

$1 + 19 + z = 100$

$20 + z = 100$

$z = 80$

So, we have $x=1$, $y=19$, and $z=80$.

Let's verify the solution:

$1 + 19 + 80 = 100$

$1(1) + 5(19) + 0.05(80) = 1 + 95 + 4 = 100$

3. Final Answer

You should take 1 horse, 19 elephants, and 80 chickens.