We are asked to solve the equation $\frac{y}{4} - \frac{2y}{3} = 16$ for $y$.

AlgebraLinear EquationsFractionsSolving Equations
2025/7/20

1. Problem Description

We are asked to solve the equation y42y3=16\frac{y}{4} - \frac{2y}{3} = 16 for yy.

2. Solution Steps

First, find a common denominator for the fractions. The least common multiple of 4 and 3 is
1

2. Multiply both sides of the equation by 12:

12(y42y3)=12(16)12(\frac{y}{4} - \frac{2y}{3}) = 12(16)
Distribute the 12 on the left side:
12y4122y3=19212 \cdot \frac{y}{4} - 12 \cdot \frac{2y}{3} = 192
Simplify the fractions:
3y4(2y)=1923y - 4(2y) = 192
3y8y=1923y - 8y = 192
Combine like terms:
5y=192-5y = 192
Divide both sides by -5 to solve for yy:
y=1925y = \frac{192}{-5}
y=1925y = -\frac{192}{5}

3. Final Answer

y=1925y = -\frac{192}{5}